What are the asymptotes of $y = \frac{x^{2}}{x^{2} - 1}$ $y=x^2/(x^2-1)$ and how do you graph the function?

Question

What are the asymptotes of $y = \frac{x^{2}}{x^{2} - 1}$ $y=x^2/(x^2-1)$ and how do you graph the function?

1 Answer

Impact of this question

7311 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-28T10:43:33

$x^{2} - 1$ $x^2-1$ can be factorized into $(x - 1) (x + 1)$ $(x-1)(x+1)$

Explanation:

Both $x = + 1$ $x=+1$ and $x = - 1$ $x=-1$ are the vertical asymptotes, as they would make the denominator $= 0$ $=0$ and the function undefined.

As $x$ $x$ gets larger (positive or negative) the function looks more and more like $\frac{x^{2}}{x^{2}} = 1$ $x^2/x^2=1$ , so $y = 1$ $y=1$ is another (horizontal) asymptote.

graph{x^2/(x^2-1) [-10, 10, -5, 5]}

Science

Math

Humanities

... and beyond

What are the asymptotes of $y = \frac{x^{2}}{x^{2} - 1}$ $y=x^2/(x^2-1)$ and how do you graph the function?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What are the asymptotes of y=x^2/(x^2-1)y=x2x2−1y=x^2/(x^2-1) and how do you graph the function?

1 Answer

Explanation:

Related questions

Impact of this question

What are the asymptotes of $y = \frac{x^{2}}{x^{2} - 1}$ $y=x^2/(x^2-1)$ and how do you graph the function?