What are the asymptotes of $y = - \frac{3}{x}$ $y=-3/x$ and how do you graph the function?

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Answer 1 · 2017-05-16T04:02:40

Vertical asymptote at $x = 0$ $x = 0$
Horizontal asymptote at $y = 0$ $y = 0$

Given: $y = - \frac{3}{x}$ $y = -3/x$

For Rational functions of the form $(N(x))/(D(x)) = (a_nx^n + ...)/(b_mx^m + ...)$ .

To find vertical asymptotes, set $D(x) = 0$ :
$D(x) = x = 0$

To find horizontal asymptotes:
When $n < m" "$ horizontal asymptote: $" " y = 0$

When $n = m " "$ horizontal asymptote: $" " y = a_n/b_m$

When $n > m" "$ there is no horizontal asymptote.

For $y = -3/x, " "n = 0, m = 1 " " n< m$

Horizontal asymptote at $y = 0$

What are the asymptotes of y=-3/xy=−3xy=-3/x and how do you graph the function?