What are the asymptotes of #y=1/(x+3)# and how do you graph the function?

1 Answer
A. S. Adikesavan
Dec 21, 2016

Vertical: #uarrx--3darr#
Horizontal: #larry = 0rarr#

Explanation:

graph{y(x+3)-1=0 [-10, 10, -5, 5]} #y = 1/(x+3) to +-oo, as x to 3#

Inversely,

x 1/y-3 to +-oo, as x to 0#.

So, the asynptotes are x = -3 and y = 0.

Interestingly, the equation #y(x+3=1# represents the rectangular

hyperbola, having these asymptotes that meet at its center (-3, 0).

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