What are the absolute extrema of f(x)=(6x) / (4x+8) in[-oo,oo]? Calculus Graphing with the First Derivative Identifying Turning Points (Local Extrema) for a Function 1 Answer Jim H Jan 4, 2016 It has no absolute extrema on the real line. Explanation: lim_(xrarr-2^-)f(x) = oo and lim_(xrarr-2^+)f(x) = -oo. Answer link Related questions How do you find the x coordinates of the turning points of the function? How do you find the turning points of a cubic function? How many turning points can a cubic function have? How do you find the coordinates of the local extrema of the function? How do you find the local extrema of a function? How many local extrema can a cubic function have? How do I find the maximum and minimum values of the function f(x) = x - 2 sin (x) on the... If f(x)=(x^2+36)/(2x), 1 <=x<=12, at what point is f(x) at a minimum? How do you find the maximum of f(x) = 2sin(x^2)? How do you find a local minimum of a graph using the first derivative? See all questions in Identifying Turning Points (Local Extrema) for a Function Impact of this question 1421 views around the world You can reuse this answer Creative Commons License