Vector A points to the north and has length A. Vector B points to the east and has length B=2.0A. How do you find the magnitude of C=3.6A+B in terms of A?

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Answer 1 · 2018-04-11T06:43:46

The answer is $=4.12A$

The vectors are the following :

$vecA= <0,1> A$

$vecB= <2,0>A$

$vecC=3.6vecA+vecB$

$=(3.6 xx<0,1> )A+<2,0>A$

$= <2, 3.6> A$

The magnitude of $vecC$ is

$=||vecC|| = ||<2, 3.6>||A$

$=sqrt(2^2+3.6^2)A$

$=4.12A$