Using the unit circle, how do you find the value of the trigonometric function: $sec -(pi/2)$ ?

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Answer 1 · 2018-03-12T02:54:45

$sec -(pi/2) = oo$

enter image source here

$-(pi/2) = 2pi - pi/2 = (3pi)/2$ . It’s in III quadrant.

As per unit circle, coordinates are (0,-1)#

#cos theta = enter image source here

$cos (-pi/2) = cos (pi/2) = 0$

Hence $sec - (pi/2) = 1 / (cos -(pi/2)) = 1 / cos (pi/2) = 1/ 0 = oo$

Using the unit circle, how do you find the value of the trigonometric function: sec -(pi/2)sec -(pi/2)?