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Using the unit circle, how do you find the value of the trigonometric function: #sec -(pi/2)#?

1 Answer

sankarankalyanam

Mar 12, 2018

#sec -(pi/2) = oo#

Explanation:

enter image source here

#-(pi/2) = 2pi - pi/2 = (3pi)/2#. It’s in III quadrant.

As per unit circle, coordinates are (0,-1)#

#cos theta = enter image source here

#cos (-pi/2) = cos (pi/2) = 0#

Hence #sec - (pi/2) = 1 / (cos -(pi/2)) = 1 / cos (pi/2) = 1/ 0 = oo#

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