Using the equation for kinetic energy: #k=1/2mv^2# Find the instantaneous rate of change of the kinetic energy of a #1500 kg# car which has a velocity of #80 m/s# and an acceleration of #10m/s^2#?

1 Answer
A08 · mason m
Mar 23, 2017

Kinetic energy #KE =1/2mv^2#
Instantaneous rate of change of KE is its differential with time
#dot (KE)=d/dt (1/2mv^2)#
#=>dot (KE)=1/2m*2v* (dv)/dt#
#=>(dot KE)=m*v*a#
Where #dot v=a#, acceleration.
Inserting given instantaneous values we get

#=>dot (KE)=1500*80*10#
#=>dot (KE)=1.2*10^6Js^-1#

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