Using the equation for kinetic energy: k=1/2mv^2 Find the instantaneous rate of change of the kinetic energy of a 1500 kg car which has a velocity of 80 m/s and an acceleration of 10m/s^2?

1 Answer
Mar 23, 2017

Kinetic energy KE =1/2mv^2
Instantaneous rate of change of KE is its differential with time
dot (KE)=d/dt (1/2mv^2)
=>dot (KE)=1/2m*2v* (dv)/dt
=>(dot KE)=m*v*a
Where dot v=a, acceleration.
Inserting given instantaneous values we get

=>dot (KE)=1500*80*10
=>dot (KE)=1.2*10^6Js^-1