Two rhombuses have sides with lengths of #6 #. If one rhombus has a corner with an angle of #pi/12 # and the other has a corner with an angle of #(11pi)/12 #, what is the difference between the areas of the rhombuses?

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Answer 1 · 2016-03-24T05:34:53

difference between areas#=0#

For the first rhombus, we compute the area:
Area#=s*s*sin (pi/12)=6*6*sin (pi/12)=36*0.258819#
Area#=9.31749#

For the second rhombus, we compute the area:
Area#=s*s*sin ((11pi)/12)=6*6*sin ((11pi)/12)=36*0.258819#
Area#=9.31749#

They have the same area measurements, therefore , difference is zero.

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