Two corners of an isosceles triangle are at (4 ,8 ) and (5 ,3 ). If the triangle's area is 5 , what are the lengths of the triangle's sides?

1 Answer
Dec 11, 2017

Measure of the three angles are (2.55, 3.2167, 3.2167)

Explanation:

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Length a = sqrt((5-4)^2 + (3-8)^2) = sqrt 26 = 5.099

Area of Delta = 5
:. h = (Area) / (a/2) = 5 / (5.099/2) = 5 / 2.55 = 1.9608
side b = sqrt((a/2)^2 + h^2) = sqrt((2.55)^2 + (1.9608)^2)
b = 3.2167

Since the triangle is isosceles, third side is also = b = 3.2167

Measure of the three sides are (2.55, 3.2167, 3.2167)