Two bodies of masses $m 1$ $m1$ and $m 2$ $m2$ are separated by a distance $R$ $R$ .The distance of the centre of mass of the bodies from the mass $m 1$ $m1$ is $A . \frac{m 2 R}{m 1 + m 2}$ $A.(m2R)/(m1+m2)$ . $B \frac{m 1 R}{m 1 + m 2}$ $B(m1R)/(m1+m2)$ #C. (m1m2R)/(m1+m2) ?

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Answer 1 · 2018-03-18T04:44:39

$A$ $A$

Let the centre of mass of the system lies at a distance $x$ $x$ from $m_{1}$ $m_1$ ,

so,we can say,

$(m_{1} + m_{2}) x = m_{1} \cdot 0 + m_{2} R$ $(m_1 +m_2)x=m_1*0 +m_2R$

or, $x = \frac{m_{2} R}{m_{1} + m_{2}}$ $x=(m_2R)/(m_1+m_2)$

Two bodies of masses m1m1 and m2m2 are separated by a distance RR.The distance of the centre of mass of the bodies from the mass m1m1 is A.m2Rm1+m2A.(m2R)/(m1+m2). Bm1Rm1+m2B(m1R)/(m1+m2) #C. (m1m2R)/(m1+m2) ?