There are $20$ players on each of two baseball teams. If $2/5$ of the players on team 1 miss practice and $1/4$ of the players on team 2 miss practice, how many more players from team 1 missed practice then team 2?

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Answer 1 · 2018-04-03T09:19:25

3

$2/5 of 20 =2/5$ $xx$ 20

$=>$ $40/5$ = 8

So 8 players from team 1 miss training

$1/4 of 20 = 1/4$ $xx$ 20

$=>$ $20/4 = 5$

So 5 players from team 2 miss training

8 -5 =3

There are 2020 players on each of two baseball teams. If 2/52/5 of the players on team 1 miss practice and 1/41/4 of the players on team 2 miss practice, how many more players from team 1 missed practice then team 2?