The sum of three consecutive odd integers is 351, how do you find the three integers?

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The sum of three consecutive odd integers is 351, how do you find the three integers?

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Answer 1 · 2018-05-04T20:31:56

I got: $115,117 and 119$

Explanation:

let us call our integers:
$2n+1$
$2n+3$
$2n+5$
we get:
$2n+1+2n+3+2n+5=351$
rearrange:
$6n=351-9$
so that:
$n=342/6=57$
our integers will then be:
$2n+1=115$
$2n+3=117$
$2n+5=119$

Answer 2 · 2018-05-04T20:39:06

115, 117 & 119

Explanation:

We can represent the three integers by using the variable $x$

1st odd integer $=x$
2nd odd integer $=x+2$ consecutive integers would be $x+1$
3rd odd integer $=x+4$

The sum means we need to add

$x + x +2 + x + 4 = 351$

Combine like terms
$3x + 6 = 351$

Use additive inverse to isolate the variable term
$3x cancel(+6) cancel(-6)= 351-6$

$3x = 345$

Use the multiplicative inverse to isolate the variable
$(cancel3x)/cancel3 = 345/3$

$x =115$
$x+2=117$
$x + 4 = 119$

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The sum of three consecutive odd integers is 351, how do you find the three integers?

2 Answers

Explanation:

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