The sum of 3 consecutive odd numbers is 27, how do you find the numbers?

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Answer 1 · 2016-02-06T05:42:28

Remember that consecutive integers differ in the value of $2$ :

Let the first no. be $x$ :
Then,second no.= $x+2$
Third no.= $x+4$

So,

$rarr(x)+(x+2)+(x+4)=27$

$rarrx+x+2+x+4=27$

$rarr3x+6=27$

$rarr3x=27-6$

$rarr3x=21$

$x=21/3=37$

So,First no= $x=7$
Second no.= $x+2=7+2=9$
Third no.= $x+4=7+4=11$

The three nos. are $7,9 and 11$