The standard form of y = 6(x - 1)^3 ­- 8(x-3)^2?

1 Answer
ProfLayton
Apr 15, 2016

y = 6x^3-26x^2+66x-78

Explanation:

The easiest way to go about this is by expanding and simplifying.
These are the two expansions you'll need to know to solve this:
Expansion of (a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3
Expansion of (a+b)^2 = a^2 + 2ab + b^2

Applying these two formulas, we can get the final answer:
y = 6(x-1)^3 - 8(x-3)^2
y = 6(x^3-3x^2+3x-1) - 8(x^2-6x+9)
y = 6x^3-18x^2+18x-6 - 8x^2+48x-72
y = 6x^3-26x^2+66x-78

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