The solubility of manganese(II) sulphate at 20oC is 62.9g/100g H2O. How many grams of manganous(II)sulphate penta-hydrate crystal must be added to 51L H2O to make a saturated solution?

1 Answer
anor277
Oct 25, 2017

Well you gots #51*L# water.....and you need approx. #51*kg# of the hydrate.....

Explanation:

And we got #51*Lxx1000*g*"water"*L^-1xx(62.9*g*"salt")/(100*g*"water")#

#=32079*g#

And so we need to add a trifle over #32*kg# with respect to #MnSO_4(s)#.....i.e. #(32.08xx10^3*g)/(152.0*g*mol^-1)=211.05*mol#.

And with respect to the pentahydrate, this represents a mass of....

#211.05*molxx241.05*g*mol^-1=50.9*kg#....

And by the way what does #"saturated solution"# mean?

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