The rate of rotation of a solid disk with a radius of $8 m$ $8 m$ and mass of $5 k g$ $5 kg$ constantly changes from $5 H z$ $5 Hz$ to $17 H z$ $17 Hz$ . If the change in rotational frequency occurs over $3 s$ $3 s$ , what torque was applied to the disk?

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The rate of rotation of a solid disk with a radius of $8 m$ $8 m$ and mass of $5 k g$ $5 kg$ constantly changes from $5 H z$ $5 Hz$ to $17 H z$ $17 Hz$ . If the change in rotational frequency occurs over $3 s$ $3 s$ , what torque was applied to the disk?

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Answer 1 · 2017-11-11T01:33:16

$4021.2 Nm$ $"4021.2 Nm"$ of torque was applied to disc.

Explanation:

Torque is rate of change of angular momentum.

$T = (I(omega_f - ω_i))/t$

$= (I2pi(f_f - f_i))/t$

$= ((mr^2)/2 2pi(f_f - f_i))/t$ ………[∵ Moment of inertia of disc about is central axis is $(mr^2)/2$ ]

$= (("5 kg × (8 m)"^2)/2 × 2 π (17 - 5) "Hz")/"3 s" = "4021.2 Nm"$

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The rate of rotation of a solid disk with a radius of $8 m$ $8 m$ and mass of $5 k g$ $5 kg$ constantly changes from $5 H z$ $5 Hz$ to $17 H z$ $17 Hz$ . If the change in rotational frequency occurs over $3 s$ $3 s$ , what torque was applied to the disk?

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Explanation:

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The rate of rotation of a solid disk with a radius of 8 m8m8 m and mass of 5 kg5kg5 kg constantly changes from 5 Hz5Hz5 Hz to 17 Hz17Hz17 Hz. If the change in rotational frequency occurs over 3 s3s3 s, what torque was applied to the disk?

1 Answer

Explanation:

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The rate of rotation of a solid disk with a radius of $8 m$ $8 m$ and mass of $5 k g$ $5 kg$ constantly changes from $5 H z$ $5 Hz$ to $17 H z$ $17 Hz$ . If the change in rotational frequency occurs over $3 s$ $3 s$ , what torque was applied to the disk?