The punter stands on the 22 yard (roughly a meter) line to the left of the 50 yard line and the ball is kicked with an initial velocity of 25.3 m/s at an angle of 58.5° above the ground. Where does the ball land?

1 Answer
Sep 26, 2015

The ball will land at approximately the 14 yard line on the opposite side of the field.

Explanation:

launch angle: 58.5o
initial velocity: vi=25.3m/s

Vertical Motion Required to Find Time

initial vertical velocity: viy=25.3m/ssin58.5o=21.6m/s

final vertical velocity: 21.6m/s

time:
vfy=viy+gt

21.6m/s=21.6m/s+(9.81m/s2)t

43.2m/s=(9.81m/s2)t

43.2m/s9.8m/s2=t

t=4.40s

Horizontal Motion

initial horizontal velocity: vix=25.3m/scos58.5o=13.2m/s

range: x=xixt=13.2m/s4.40s=58.1m

Because an American football field is marked in yards, convert 58.1m to yards.

58.1m×1.094yd1m=63.664yards

The ball started out on the 22 yard line and traveled an additional 64 yards. An American football field is 100 yards in length. The 50 yard line is in the center.

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The location of the ball at the end of its flight will be (5022)(5036)=14

The ball will land at approximately the 14 yard line on the other side of the 50 yard line.