The pressure in a bicycle tire is 1.34 atm at 33.0°C. At what temperature will the pressure inside the tire be 1.60 atm if volume is constant?

1 Answer
Meave60
Dec 22, 2015

The temperature will be 366 K.

Explanation:

This is an example of Gay-Lussac's law in which the pressure and Kelvin temperature are directly proportional at constant volume. The equation to use is #P_1/T_1=P_2/T_2#.

#P_1="1.34 atm"#
#T_1="33.0"^"o""C"+273.15="306.2 K"#
#P_2="1.60 atm"#
#T_2="???"#

Solution
Rearrange the equation to isolate #T_2# and solve.
#P_1/T_1=P_2/T_2#

#T_2=(P_2T_1)/P_1#

#T_2=(1.60cancel"atm"xx306.2"K")/(1.34cancel"atm")#

#T_2="366 K"#

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