The position of an object moving along a line is given by $p(t) = t-cos(( pi )/4t)$ . What is the speed of the object at $t = 2$ ?

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Answer 1 · 2016-05-03T15:36:11

$v(2)=(4+pi)/4$

$v(t)=d/(d t) p(t)$

$v(t)=d/(d t)(t-cos(pi/4 *t))$

$v(t)=1+pi/4*sin(pi/4*t)$

$"for t=2 " ->v(2)=1+pi/4*sin(pi/4*2)$

$v(2)=1+pi/4*1$

$v(2)=1+pi/4$

$v(2)=(4+pi)/4$

The position of an object moving along a line is given by p(t) = t-cos(( pi )/4t) p(t) = t-cos(( pi )/4t) . What is the speed of the object at t = 2 t = 2 ?