The position of an object moving along a line is given by $p(t) = 2t - t^2cos(( pi )/3t)$ . What is the speed of the object at $t = 5$ ?

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Answer 1 · 2016-04-21T11:00:51

$p(t) = 2t - t^2cos(pi/3t)$

The speed is given as:

$v(t) = dotp(t) = 2+2pi/3tsin(pi/3t)$

so,

$v(5) = 2+(2pi)/3*5*sin((5pi)/3) ~~ 2 +(2pi)/3*5*(-0.87) = -7.11$

The position of an object moving along a line is given by p(t) = 2t - t^2cos(( pi )/3t) p(t) = 2t - t^2cos(( pi )/3t) . What is the speed of the object at t = 5 t = 5 ?