The position of an object moving along a line is given by $p(t) = 2t^3 - 5t^2 +2$ . What is the speed of the object at $t = 2$ ?

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Answer 1 · 2017-08-03T22:15:45

I got $4m/s$

We can derive our position function to find the average velocity and then evaluate it a our instant to get the instantaneous one.
We get:

$v(t)=(dp(t))/dt=6t^2-10t$

at $t=2$

$v(2)=6*4-10*2=24-20=4m/s$

The position of an object moving along a line is given by p(t) = 2t^3 - 5t^2 +2p(t) = 2t^3 - 5t^2 +2. What is the speed of the object at t = 2 t = 2 ?