The position of an object moving along a line is given by $p(t) = 2t^3 - 2t^2 +1$ . What is the speed of the object at $t = 4$ ?

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Answer 1 · 2016-05-03T08:51:35

$v(4)=80$

$v(t)=d/(d t) p(t)$

$v(t)=d/(d t) (2t^3-2t^2+1)$

$v(t)=6t^2-4t+0$

$"if" " t=4 " ->" "v(4)=6*4²-4*4=96-16=80$

$v(4)=80$

The position of an object moving along a line is given by p(t) = 2t^3 - 2t^2 +1p(t) = 2t^3 - 2t^2 +1. What is the speed of the object at t = 4 t = 4 ?