The position of a particle moving along the x-axis is given by x(t)=t^3-9t^2+24tx(t)=t39t2+24t meters where t is in seconds, t>=0t0 a) Draw a sign diagram for the particle's velocity and acceleration functions.?

t>=0t0

1 Answer
Jan 21, 2018

See the explanation below

Explanation:

The velocity is the derivative of the position

x(t)=t^3-9t^2+24tx(t)=t39t2+24t

v(t)=3t^2-18t+24=3(t^2-6t+8)v(t)=3t218t+24=3(t26t+8)

=3(t-2)(t-4)=3(t2)(t4)

The acceleration is the derivative of the velocity

v(t)=3t^2-18t+24v(t)=3t218t+24

a(t)=6t-18=6(t-3)a(t)=6t18=6(t3)

The sign chart for the velocity is as follows :

color(white)(aaaa)aaaattcolor(white)(aaaaa)aaaaa00color(white)(aaaaaaaa)aaaaaaaa22color(white)(aaaaaaaa)aaaaaaaa44color(white)(aaaaaa)aaaaaa+oo+

color(white)(aaaa)aaaat-2t2color(white)(aaaaaa)aaaaaa-color(white)(aa)aa00color(white)(aaa)aaa++color(white)(aaaaaa)aaaaaa++

color(white)(aaaa)aaaat-4t4color(white)(aaaaaa)aaaaaa-color(white)(aa)aa#color(white)(aaaa)-#color(white)(aaa)aaa00color(white)(aa)aa++

color(white)(aaaa)aaaav(t)v(t)color(white)(aaaaaa)aaaaaa++color(white)(aaa)aaa00color(white)(aaa)aaa-color(white)(aaa)aaa00color(white)(aa)aa++

color(white)(aaaa)aaaas(t)s(t)color(white)(aaaaaa)aaaaaacolor(white)(aa)aa2020color(white)(aaa)aaacolor(white)(aa)aa1616color(white)(aa)aa

The sign chart fot the acceleration is as follows :

color(white)(aaaa)aaaa"Interval"Intervalcolor(white)(aaaa)aaaa(0,3)(0,3)color(white)(aaaa)aaaa(3,+oo)(3,+)

color(white)(aaaa)aaaaa(t)a(t)color(white)(aaaaaaaaa)aaaaaaaaa-color(white)(aaaaaaa)aaaaaaa++

color(white)(aaaa)aaaas(t)s(t)color(white)(aaaaaaaaa)aaaaaaaaanncolor(white)(aaaaaaa)aaaaaaauu

graph{(y-(x^3-9x^2+24x))(y-(3x^2-18x+24))(y-(6x-18))=0 [-23.9, 41.07, -6.7, 25.78]}