The pH of a solution changes fro 300 to 6.00. By what factor does the #[H_3O^+]# change?

1 Answer
anor277
Feb 26, 2017

By a factor of #1000#.

Explanation:

#pH=-log_10[H_3O^+]#

If #pH_1=3.00#, then #[H_3O^+]=10^-3*mol*L^-1.#

If #pH_2=6.00#, then #[H_3O^+]=10^-6*mol*L^-1.#

#(pH_1)/(pH_2)=(10^-3*mol*L^-1)/(10^-6*mol*L^-1)=10^3#

The latter concentration is less concentrated with respect to #H_3O^+# than the former by a factor of #1000#.

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