The number of square tiles needed to tile a square floor is equal to $a^{2} \div b^{2}$ $a^2 -: b^2$ , where $a$ $a$ is the floor length in inches and $b$ $b$ is the length of the tile in inches. If $a = 96$ $a = 96$ and $b = 8$ $b =8$ , how many tiles are needed?

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Answer 1 · 2018-05-17T05:13:41

144

No. of square tiles needed = $\frac{a^{2}}{b^{2}}$ $a^2/b^2$

So, if $a = 96$ $a=96$ and $b = 8$ $b=8$ , then all you do is you have to sub into your 2 numbers into the equation

No. of square tiles needed = $\frac{96^{2}}{8^{2}} = 144$ $96^2/8^2 = 144$

Answer 2 · 2018-05-17T05:16:27

$144$ $144$ tiles are needed.

Area of floor is $96^{2}$ $96^2$ square inches and

area of each tile is $8^{2}$ $8^2$ square inches

Hence, number of tiles needed are

$\frac{96 \times 96}{8 \times 8}$ $(96xx96)/(8xx8)$

= $(cancel96^12xxcancel96^12)/(cancel8^1xxcancel8^1)$

= $12xx12$

= $144$

The number of square tiles needed to tile a square floor is equal to a^2 -: b^2a2÷b2a^2 -: b^2, where aaa is the floor length in inches and bbb is the length of the tile in inches. If a = 96a=96a = 96 and b =8b=8b =8, how many tiles are needed?