The length of a rectangle is 5 yd more than twice its width, and the area of the rectangle is 42yd^2 . How do I find the dimensions of the rectangle?

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Answer 1 · 2016-09-27T03:22:13

Let the length be #2x + 5# and the width be #x#.

#x(2x + 5) = 42#

#2x^2 + 5x = 42#

#2x^2 + 5x - 42 = 0#

#2x^2 + 12x - 7x - 42 =0#

#2x(x + 6) - 7(x+ 6) = 0#

#(2x - 7)(x + 6) = 0#

#x = 7/2 and -6#

Hence, the dimensions are #7/2# by #12# yards.

Hopefully this helps!