The hydrogen oxalate ion is amphoteric. Write two balanced chemical equations to illustrate this property. What is the conjugate acid of this ion and what is its conjugate base?

1 Answer
Dec 9, 2015

See explanation.

Explanation:

As you know, an amphoteric compound can act both as a Bronsted - Lowry acid and a Bronsted - Lowry base.

More specifically, the hydrogen oxalate ion, "HC"_2"O"_4^(-)HC2O4, will act as an acid by donating a proton, "H"^(+)H+, and as a base by accepting a proton.

Now, what would you expect to see when the hydrogen oxalate ion acts as an acid in aqueous solution?

Well, since it donates a proton, its net charge will go from 1-1 to 2-2, since a proton carries a 1+1+ charge.

Moreover, the acidity of the solution should increase, i.e. its pH should decrease. This tells you that the concentration of hydronium ions, "H"_3"O"^(+)H3O+, should Increase.

"CH"_2"O"_text(4(aq])^(-) + "H"_2"O"_text((l]) rightleftharpoons "C"_2"O"_text(4(aq])^(2-) + "H"_3"O"_text((aq])^(+)CH2O4(aq]+H2O(l]C2O24(aq]+H3O+(aq]

The conjugate base of a Bronsted - Lowry acid is the chemical species that remains after the acid donates a proton.

In this case, the oxalate anion, "C"_2"O"_4^(2-)C2O24, will be the hydrogen oxalate ion's conjugate base.

How about when the hydrogen oxalate acts as a base in aqueous solution?

Well, this time it's accepting a proton, so its charge will go from 1-1 to 00.

Moreover, the basicity of the solution will Increase, i.e. its pH will increase. This tells you that teh concentration of hydroxide ions, "OH"^(-)OH, will increase.

"CH"_2"O"_text(4(aq])^(-) + "H"_2"O"_text((l]) rightleftharpoons "H"_2"C"_2"O"_text(4(aq]) + "OH"_text((aq])^(-)CH2O4(aq]+H2O(l]H2C2O4(aq]+OH(aq]

The conjugate acid of a Bronsted - Lowry base is the chemical species that remains after the base accepts a proton.

In this case, oxalic acid, "H"_2"C"_2"O"_4H2C2O4, is the hydrogen oxalate's conjugate acid.