The half-life of radon-222 is 3.82 days. If a sample of gas contains 4.38 #mug# of radon-222, how much will remain in the ample after 15.2 days?

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Answer 1 · 2016-12-21T10:31:32

The answer is #=0.278 mug#

We use the following equations

#N(t)=N_0e^(-lambdat)#

and #lambda=(ln2)/t_(1/2)#

The half life is #t_(1/2)=3.82#

#N_0=4.38 mug#

#lambda=(ln2)/3.82=0.1815 d^(-1)#

#N(15.2 d)=4.38*e^(-0.1815*15.2)#

#=0.278 mug#