The half life of a radioactive isotope is 350 years. How do you find the amount remaining after 800 years, if the initial amount is 64 grams?

Question

1848 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-29T15:29:27

The amount remaining #=13.13g#

Use the equation

#N(t)=N_0e^(-lambdat)#

#N_0=#initial amount #=64 g#

The half life is #=t_(1/2)=ln2/lambda#

#t_(1/2)=350 y#

Therefore, #lambda=ln2/350 y^(-1)#

#t=800y#

#N(t)=64*e^((-ln2/350)*800)#

#=13.13g#