The half life of a radioactive isotope is 350 years. How do you find the amount remaining after 800 years, if the initial amount is 64 grams?

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Answer 1 · 2016-11-29T15:29:27

The amount remaining #=13.13g#

Use the equation

#N(t)=N_0e^(-lambdat)#

#N_0=#initial amount #=64 g#

The half life is #=t_(1/2)=ln2/lambda#

#t_(1/2)=350 y#

Therefore, #lambda=ln2/350 y^(-1)#

#t=800y#

#N(t)=64*e^((-ln2/350)*800)#

#=13.13g#