The formula for the illegal drug cocaine is #C_17H_21NO_4#, which is 303.39 g/mol. What is the percentage of carbon in the compound? Chemistry The Mole Concept Percent Composition 1 Answer anor277 May 5, 2016 Approx. 70% Explanation: #"%Carbon"# #=# #"Mass of carbon"/"Mass of molecule"# #xx100%# #=# #(17xx12.011*g*mol^-1)/(303.39*g*mol^-1)# #xx100%# #=# #??%# Answer link Related questions What is mole percent? Question #e2e8b Question #bc737 Question #bc73b Question #e2e8f Question #b9857 Question #b985b Question #fee41 Question #c5c01 Question #bc73f See all questions in Percent Composition Impact of this question 11737 views around the world You can reuse this answer Creative Commons License