The first term of geometric sequence is 512 and the common ratio is 0.5 what is the 8th term of the sequence?

Question

12117 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-14T18:10:18

The $8^(th) term$ of the seqn, is : $a_8=4$

We know that,

the $n^(th) term$ of geometric sequeence is:

$a_n=a_1 r^(n-1)$

where $a_1$ is first term and $r$ is common ratio.

We have, $a_1=512 and r=0.5=1/2$

So, the $8^(th) term$ of the seqn, is :

$a_8=a_1(r)^(8-1)$

$:.a_8=512(1/2)^7=512xx1/128=4$