The empirical formula of a compound is determined to be $"C"_2"H"_3$ , and its molecular mass is found to be 54.10 g/mol. How do you determine the molecular formula of the compound?

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Answer 1 · 2016-11-29T23:05:41

$"C"_4"H"_6$

We simply divide the molecular mass by the empirical mass and multiply the result by the number of molecules in the compound.

$54.1/27approx2$

$"C"_2"H"_3xx2="C"_4"H"_6$

The empirical formula of a compound is determined to be "C"_2"H"_3"C"_2"H"_3, and its molecular mass is found to be 54.10 g/mol. How do you determine the molecular formula of the compound?