The diameter of a chlorine atom is 200. pm. How many chlorine atoms are required to line up end to end to stretch a distance of 1.0 mm?

1 Answer
Aug 28, 2016

Good question. (1xx10^-3*m)/(200xx10^-12*m)

Explanation:

(1xx10^-3*m)/(200xx10^-12*m) = ??

A more realistic measurement might consider the chlorine molecule. Cl_2 has a bond length of 2.00xx10^-10 m. How many of these ened to end will fit in a mm. Pretty vast but not infinite.