The density (in g/L) of helium (He) gas at 723 torr and 225 K is?

Question

How many g/L ?

3844 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-10-23T06:35:52

#rho=0.2*g*L^-1#

Now #PV=nRT#.....and thus #P/(RT)=n/V=("mass"/"molar mass")/V#

And so #P/(RT)xx"molar mass"="mass"/V=rho_"helium"# as required...

ANd we assume of molar quantity of #1*mol# under the given conditions....

#rho_"helium"=((723*"Torr")/(760*"Torr"*atm^-1)xx4.003*g*mol^-1)/(0.0821(L*atm)/(K*mol)xx225*K)#

#=0.206*g*L^-1#