The boiling point of ethanol is 78°C. What would it be in kelvin?
1 Answer
Mar 13, 2016
Explanation:
- Derive formula from the following data:
Boiling Pt of water
#K=373#
#C=100^o#
Freezing Pt of Water
#K=273#
#C=0^o# - Write the ratio of the 2 temperature scales with the zero points and the unit sizes
#(K-273)/(373-273)=(C-0)/(100-0)# - Simplify
#(K-273)/cancel100=C/cancel100# - 100 are cancelled since these 2 scales have same unit sizes so that the formula is;
#K-273=C# - Isolate
#K# by adding 273 both sides of the equation
#K=C+273# - Plug in the given data
#C=78^o# to the derived formula - The answer is
#351K#
