T is a real number and P=(square root of 3/2, 1/2) is the point on the unit circle that corresponds to t. How do you find the exact values of six trigonometric functions of t?

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Answer 1 · 2018-03-20T13:23:52

See explanation.

Given the point $P=(sqrt(3)/2;1/2)$ on the angle's side we have:

$x=sqrt(3)/2$ , $y=1/2$

$r=sqrt(x^2+y^2)=sqrt(3/4+1/4)=1$

Now we can calculate the trig. functions:

$sinT=y/r=1/2$