Suppose that 11 inches of wire costs 44 cents. At the same rate, how much (in cents) will 28 inches of wire cost?

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Suppose that 11 inches of wire costs 44 cents. At the same rate, how much (in cents) will 28 inches of wire cost?

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Answer 1 · 2017-08-19T21:24:47

See a solution process below:

Explanation:

Let's call the amount the 28 inches of wire will cost: $c$ $c$

We can then write and solve for $c$ $c$ :

$\frac{44 cents}{11 in} = \frac{c}{28 in}$ $(44" cents")/(11" in") = c/(28" in")$

$28 in \times \frac{44 cents}{11 in} = 28 in \times \frac{c}{28 in}$ $color(red)(28" in") xx (44" cents")/(11" in") = color(red)(28" in") xx c/(28" in")$

$color(red)(28color(black)(cancel(color(red)(" in")))) xx (44" cents")/(11color(red)(cancel(color(black)(" in")))) = cancel(color(red)(28" in")) xx c/color(red)(cancel(color(black)((28" in"))$

$(28 xx 44" cents")/11 = c$

$(28 xx color(red)(cancel(color(black)(44)))4" cents")/color(red)(cancel(color(black)(11))) = c$

$28 xx 4" cents" = c$

$112 = c$

$c = 112$

28 inches of wire will cost 112 cents.

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Suppose that 11 inches of wire costs 44 cents. At the same rate, how much (in cents) will 28 inches of wire cost?

1 Answer

Explanation:

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