Suppose a random variable #x# is best described by a uniform probability distribution with range 1 to 6. What is the value of #a# that makes #P(x < a) = 0.62# true?

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Answer 1 · 2017-10-17T12:44:20

#a=4.1#

the diagram represents the distribution
enter image source here

It is uniform so its graph is a rectangle with area #=1#

first we have to find

(6-1)k=1#

#=>k=1/5#

#P(X< a )=0.62#

so this will be the area to the left of #a# in the diagram

#:.(a-1)xx1/5=0.62#

now solve for #a#

#a-1=0.62xx5=3.1#

#=>a=3.1+1=4.1#