Suppose a random variable $x$ $x$ is best described by a uniform probability distribution with range 1 to 6. What is the value of $a$ $a$ that makes $P (x < a) = 0.62$ $P(x < a) = 0.62$ true?

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Answer 1 · 2017-10-17T12:44:20

$a = 4.1$ $a=4.1$

the diagram represents the distribution
enter image source here

It is uniform so its graph is a rectangle with area $= 1$ $=1$

first we have to find

(6-1)k=1#

$\Rightarrow k = \frac{1}{5}$ $=>k=1/5$

$P (X < a) = 0.62$ $P(X< a )=0.62$

so this will be the area to the left of $a$ $a$ in the diagram

$:.(a-1)xx1/5=0.62$

now solve for $a$

$a-1=0.62xx5=3.1$

$=>a=3.1+1=4.1$

Suppose a random variable xxx is best described by a uniform probability distribution with range 1 to 6. What is the value of aaa that makes P(x < a) = 0.62P(x<a)=0.62P(x < a) = 0.62 true?