Soybean meal is 16% protein cornmeal is 8% protein how many pounds of each should be mixed together in order to get 320 lb mixture that is 14% protein how many pounds of cornmeal should be in the mixture?

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Answer 1 · 2018-04-19T12:24:53

$240$ $240$ pounds of Soybean meal to be mixed with $80$ $80$ pounds of Corn meal to get $320$ $320$ pounds mixture.

Let $x$ $x$ pounds of Soybean meal of $16 %$ $16%$ protein is mixed

with $(320 - x)$ $(320-x)$ pounds of Corn meal of $8 %$ $8%$ protein to get

$320$ $320$ pounds mixture of $14 %$ $14%$ protein. Equating protein

content we get, $0.16 x + (320 - x) \cdot 0.08 = 320 \cdot 0.14$ $0.16 x+ (320-x) *0.08 =320 *0.14$ or

$0.16 x - 0.08 x + 25.6 = 44.8 or 0.08 x = 44.8 - 25.6$ $0.16 x - 0.08 x+ 25.6 = 44.8 or 0.08 x = 44.8-25.6$ or

$0.08 x = 19.2 :. x = 19.2/0.08 =240:. 320-240= 80$ . Hence

$240$ pounds of Soybean meal of $16%$ protein to be mixed

with $80$ pounds of Corn meal of $8%$ protein to get

$320$ pounds mixture of $`14%$ protein. [Ans]