A muon (an elementary particle) moving in straight line enters a region with a speed of 5.00 x 10^6 m/s and then is slowed at the rate of 1.25 x 10^14 m/s^2. ?

A muon (an elementary particle) moving in straight line enters a region with a speed of 5.00 x 10^6 m/s and then is slowed at the rate of 1.25 x 10^14 m/s^2.

a. How far does the muon take to stop?
b. Graph x vs. t and v vs. t for the muon.

1 Answer

Distance s traveled by the muon moving with initial velocity u=5\times10^6 m/s before it comes to rest (v=0) under deceleration a=1.25\times10^{14}\ m/s^2

From third equation of motion
v^2=u^2-2as

0^2=(5\times10^6)^2-2(1.25\times10^{14})s

s=0.1\ m

The graph x vs t will be a downward parabola

The graph v vs t will be a straight line with negative slope