Solve the following?: Using the punnet square between two organisms with genotype Ff and Ff, the probabilities for the genotype of the offspring is like the following: FF=25%, Ff=50%, ff=25% (continued on details)

Question

If there were 4 offspring from the two organisms, what is the probability that there are 3 ff?

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Answer 1 · 2018-02-18T20:59:01

#3/64#

the probability of having an ff genotype is #25%#.

if there are #4# offspring, numbered #1-4#, the ff offspring could be:

#1,2,3#
#1,2,4#
#1,3,4#
#2,3,4#
where the genotype of the other offspring is Ff

there are #4# possible ways to have #3# ff offspring, with one Ff.#

the probability of having Ff is #50%#.

#25% * 25% * 25% * 50% = 0.25 * 0.25 * 0.25 * 0.5#

which is #0.0078125#

#0.0078125 * 4 = 0.03125#

the ff offspring could also be:

#1,2,3#
#1,2,4#
#1,3,4#
#2,3,4#
where the genotype of the other offspring is FF

the probability of having FF is #25%#

#0.25 * 0.25 * 0.25 * 0.25 = 0.25^4 = 0.00390625#

#0.00390625 * 4 = 0.015625#

#0.03125 + 0.015625 = 0.046875#

or #4.6875%#, #3/64#