Solve for the following equation in the interval [0, 2 $pi$ ): $3cos^2theta + sin^2theta =2$ ?

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Answer 1 · 2017-12-16T01:07:35

$theta=pi/4, (3pi)/4, (5pi)/4, (7pi)/4$

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$3cos^2theta+sin^2theta=2$

$3cos^2theta+1-cos^2theta=2$

$2cos^2theta=1$

$cos^2theta=1/2$

$costheta=+-sqrt2/2$

$theta=pi/4, (3pi)/4, (5pi)/4, (7pi)/4$

Solve for the following equation in the interval [0, 2pipi): 3cos^2theta + sin^2theta =23cos^2theta + sin^2theta =2?