Solve for b if $1-b/(4+isqrt3)+b/(4-isqrt3)=0$ ?

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Answer 1 · 2017-12-16T01:24:35

$b=(19isqrt3)/6$

$1-b/(4+isqrt3)+b/(4-isqrt3)=0$

$1-[b*(4-isqrt3)-b*(4+isqrt3)]/(16-(-3))=0$

$1-(-2bisqrt3)/19=0$

$(2bisqrt3)/19=-1$

$b=-19/(2isqrt3)$

$b=(-19isqrt3)/(-6)$

$b=(19isqrt3)/6$

Solve for *b* if 1-b/(4+isqrt3)+b/(4-isqrt3)=01-b/(4+isqrt3)+b/(4-isqrt3)=0?