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Slope of Force-position curve of a particle undergoing S.H.M is -4,find the mass of the particle if it has a time period of 0.2s ?

1 Answer

Mar 10, 2018

$4.053 g$ $4.053 g$

Explanation:

equation of S.H.M is $F = - m ω^{2} x$ $F=-momega^2x$

So,slope $= - m ω^{2} = - 4$ $=-momega^2=-4$ (given) (where, $m$ $m$ is its mass)

We know, $ω = \frac{2 π}{T} = 31.416 r a d s^{- 1}$ $omega=(2pi)/T=31.416 rads^-1$

So, $m = \frac{4}{ω^{2}} = 0.004053 K g = 4.053 g$ $m=4/omega^2=0.004053 Kg=4.053 g$

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