Sketch 4,6-diethyl-5-propylnonane and sketch 2,cyclopropylpropane?

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Answer 1 · 2017-11-18T13:45:30

Just to retire this question, you draw the 9-membered carbon backbone first....

$H_3C-CH_2CH_2CH_2CH_2CH_2CH_2CH_2CH_3$

And then you number the chain appropriately....

$H_3C-stackrel2CH_2CH_2stackrel4CH_2stackrel5CH_2stackrel6CH_2CH_2CH_2CH_3$

And then you substitute the indicated carbons with the required substituent..

$H_3C-stackrel2CH_2CH_2stackrel4CHR_1stackrel5CHR_2stackrel6CHR_1CH_2CH_2CH_3$

Where $R_1=CH_2CH_3$ , and $R_2=CH_2CH_2CH_3$ .

The three-membered ring is also easy to do; on paper but not on this editor......