$\frac{{sec}^{2} θ}{2 tan θ} =$ $sec^2theta/(2tantheta) =$ ? Explain And Answer Question

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$\frac{{sec}^{2} θ}{2 tan θ} =$ $sec^2theta/(2tantheta) =$ ? Explain And Answer Question

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Answer 1 · 2018-05-02T09:09:34

$\frac{1}{2} csc θ sec θ$ $1/2cscthetasectheta$

Explanation:

$using the trigonometric identities$ $"using the "color(blue)"trigonometric identities"$

$∙ x sec θ = \frac{1}{cos θ} and tan θ = \frac{sin θ}{cos θ}$ $•color(white)(x)sectheta=1/costheta" and "tantheta=sintheta/costheta$

$∙ x csc θ = \frac{1}{sin θ}$ $•color(white)(x)csctheta=1/sintheta$

$\Rightarrow \frac{\frac{1}{{cos}^{2} θ}}{\frac{2 sin θ}{cos θ}}$ $rArr(1/(cos^2theta))/((2sintheta)/costheta)$

$=1/(cancel(costheta)costheta)xxcancel(costheta)/(2sintheta)$

$=1/(2sinthetacostheta)$

$=1/2xx1/sinthetaxx1/costheta=1/2cscthetasectheta$

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$\frac{{sec}^{2} θ}{2 tan θ} =$ $sec^2theta/(2tantheta) =$ ? Explain And Answer Question

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sec^2theta/(2tantheta) = sec2θ2tanθ=sec^2theta/(2tantheta) = ? Explain And Answer Question

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$\frac{{sec}^{2} θ}{2 tan θ} =$ $sec^2theta/(2tantheta) =$ ? Explain And Answer Question