Sara has a fire in the fireplace to warm her 20°C apartment. She realizes that she has left the iron poker in the fire. How hot is the fire if the 0.60 m poker lengthens 0.30 cm? (αiron = 12 x 10-6°C-1)

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Sara has a fire in the fireplace to warm her 20°C apartment. She realizes that she has left the iron poker in the fire. How hot is the fire if the 0.60 m poker lengthens 0.30 cm? (αiron = 12 x 10-6°C-1)

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Answer 1 · 2015-05-13T23:53:38

You can use the expression for linear expansion as:
$Deltal=l_0alphaDeltaT$
Where $l_0$ is the initial/original length, $alpha$ is the linear expansion coefficient and $DeltaT$ is the variation of temperature.
So you get:
$0.3=60*12xx10^-6*(T_(fire)-20)$
So: $T_(fire)=437°C$

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Sara has a fire in the fireplace to warm her 20°C apartment. She realizes that she has left the iron poker in the fire. How hot is the fire if the 0.60 m poker lengthens 0.30 cm? (αiron = 12 x 10-6°C-1)

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