Resistance?

Question

`1.) In this problem, you will calculate the basic quantities in a simple electric circuit.
A 83 Ω resistor and a length of wire of resistance 18 Ω are connected in series across a 57 V power supply.
Calculate the current flowing in the circuit.
Give your answer in Amps

2.) Calculate the power dissipated in the 83 Ω resistor..
Give the answer in Watts.

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Answer 1 · 2018-02-16T20:34:41

1.) $I = 0.56" A"$

2.) $P = 26.4" W"$

The total resistance of the circuit is:

$R_"total" = 83" "Omega+18" "Omega$

$R_"total" = 101" "Omega$

The current in the circuit is the source voltage divided by the total resistance:

$I = V/R_"total"$

$I = (57" V")/(101" "Omega)$

$I = 0.564" A"$

The power dissipated by the resistor is the square of the current through it multiplied by the resistance of the resistor:

$P = I^2R$

$P = (0.564" A")^2(83" "Omega)$

$P = 26.4" W"$