Raphael paid $632 for a camera during a 20% off sale. What was the camera's regular price?

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Answer 1 · 2016-11-30T08:02:37

The camera's regular price was $$790$ .

We can express discount amount as $x$ and the original price of the camera as $x+632$ . The equation to determine the price will be:

$(x+632)xx20/100=x$

Simplify.

$(x+632)xx(1cancel(20))/(5cancel(100))=x$

Multiply both sides by $5$ .

$x+632=5x$

Subtract $x$ from both sides.

$632=4x$

Divide both sides by $4$ .

$158=x$

Since the discount amount $(x)$ is $158$ , the original price $(x+632)$ will be $(158+632)=790$ .