Radium, Ra-226, undergoes alpha decay. What is the product?

1 Answer
anor277
Mar 29, 2018

Well, an alpha-"particle"-=""_2^4He^(2+)

Explanation:

And mass and charge are (almost conserved) in nucular reactions...

""_88^226Rararr""_86^222Rn+""_2^4He^(2+) + 2e^(-)...

...and congratulations, I think this is the first time for a long time that I have had to look up an elemental symbol on the Table....I thought for a moment that "radon"-="Rd"

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